Numerical Problems
10.1. The time period of a simple pendulum is 2 s. What will be its length on the Earth? What will be its length on the Moon if gm=ge/6? where ge=10ms−2ge=10ms−2g_{\mathrm{e}} = 10 \mathrm{m} \mathrm{s}^{- 2}ge=10ms−2ge=10ms−2 .
Ans. (1.02 m, 0.17 m)
10.2. A pendulum of length 0.99m0.99m0.99 \mathrm{m}0.99m0.99m is taken to the Moon by an astronaut. The period of the pendulum is 4.9s4.9s4.9 \mathrm{s}4.9s4.9s . What is the value of ggg on the surface of the Moon?
10.3. Find the time periods of a simple pendulum of 1 metre length, placed on Earth and on Moon. The value of ggg on the surface of Moon is 1/6th1 / 6^{\text{th}}1/6th of its value on Earth, where gegeg_{\mathrm{e}}gege is 10ms−210ms−210 \mathrm{m} \mathrm{s}^{- 2}10ms−210ms−2 .
Ans. (2 s, 4.9 s)
10.4. A simple pendulum completes one vibration in two seconds. Calculate its length, when g=10.0ms−2g=10.0ms−2g = 10.0 \mathrm{m} \mathrm{s}^{- 2}g=10.0ms−2g=10.0ms−2 .
Ans. (1.02 m)
10.5. If 100 waves pass through a point of a medium in 20 seconds, what is the frequency and the time period of the wave? If its wavelength is 6cm6cm6 \mathrm{cm}6cm6cm , calculate the wave speed.
Ans. (5 Hz, 0.2 s, 0.3 m s −1^{- 1}−1 )